Saturday, April 24, 2010

MTH302 Ass Sol

 
                                 Assignment # 1
                                  MTH302 (Spring 2010)                             

                                                          Question 1:

Solution:

Basic Salary = 2,000
House Rent = 900
Utility Allowance= 200
Gross Salary =2000+900+200 = 3100

BENEFITS
$
Percent of Basic/Gross Salary
House Rent
900
900 x 2000 x 100 = 45%
Utilities Allowance
200
200/2000*100 = 10%
Medical/Group insurance
155
155/3100*100 = 5%
Miscellaneous Social Charges
186
186/3100*100 = 6%


                                                     Question 2:                                                        
Solution:
Formula:
Change = Final value – initial value
Percentage change = (Change / initial value) x 100%
Change = 70- 76
Change = -6 
Percentage change = (-6/ 76) x 100
Percentage change = -7.8947%

                                                           Question 3:
.Solution:
P = Principal= 800
r = Rate of interest= 8% = 0.08
n = Number of periods = 3*2= 6 years (Semi annually)
Formula:
Compound interest = S – P
S = P (1 + r/2) ^ n*2
S = P (1 + r/2) ^ n*2

S = 800 (1 + 0.08/2) ^ 3*2
 S = 800 (1 + 0.04) ^ 6
 S = 800 (1.04) ^ 6
 S = 1012.255
 Compound interest = 1012.255 - 800
Compound interest = 212.255 Ans.         
                                                        Question 4:
Solution:
 Cash flow per period = 500
i = interest rate = 8% = 0.08
n = number of payments = 3
Formula:
Accumulated value of n period = payment per period × accumulation factor for n Periods
Accumulated value of n period = C* [(1+i) ^n – 1]/i
= 500* [(1+0.08) ^3 – 1]/0.08
= 500* [(1.08) ^3 – 1]/0.08
= 500* [1.259712 – 1]/0.08
= 500* [0.259712]/0.08
= 500* 3.2464
=1623.2
Accumulated value of n period = 500 × 3.2464
Accumulated value of n period = 1623.2 Ans.


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